Solution 1.1:2b

From Förberedande kurs i matematik 2

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The expression is a sum of two terms which we differentiate one by one:
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<center> [[Image:1_1_2b.gif]] </center>
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<math>\begin{align}
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& {f}'\left( x \right)=\frac{d}{dx}\left( \cos x-\sin x \right) \\
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& =\frac{d}{dx}\cos x-\frac{d}{dx}\sin x=-\sin x-\cos x \\
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\end{align}</math>

Revision as of 11:00, 10 October 2008

The expression is a sum of two terms which we differentiate one by one:


\displaystyle \begin{align} & {f}'\left( x \right)=\frac{d}{dx}\left( \cos x-\sin x \right) \\ & =\frac{d}{dx}\cos x-\frac{d}{dx}\sin x=-\sin x-\cos x \\ \end{align}

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