Solution 3.1:1b
From Förberedande kurs i matematik 2
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| - | {{ | + | When we remove the parentheses, the terms inside change sign, |
| - | < | + | |
| - | {{ | + | {{Displayed math||<math>3i-(2-i)=3i-2+i\,\textrm{.}</math>}} |
| + | |||
| + | Then, we collect together real and imaginary parts, | ||
| + | |||
| + | {{Displayed math||<math>\begin{align} | ||
| + | 3i-2+i | ||
| + | &=-2+(3i+i)\\[5pt] | ||
| + | &=-2+(3+1)i\\[5pt] | ||
| + | &=-2+4i\,\textrm{.} | ||
| + | \end{align}</math>}} | ||
Current revision
When we remove the parentheses, the terms inside change sign,
| \displaystyle 3i-(2-i)=3i-2+i\,\textrm{.} |
Then, we collect together real and imaginary parts,
| \displaystyle \begin{align}
3i-2+i &=-2+(3i+i)\\[5pt] &=-2+(3+1)i\\[5pt] &=-2+4i\,\textrm{.} \end{align} |
