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Solution 1.2:1c

From Förberedande kurs i matematik 1

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We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
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<center> [[Image:1_2_1c.gif]] </center>
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{{Displayed math||<math>\frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,</math>.}}
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Then the numerators can be subtracted
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{{Displayed math||<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,</math>.}}

Current revision

We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,

61−52=6515−5626=530−3012.

Then the numerators can be subtracted

530−3012=305−12=30−7=−730.
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