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Solution 4.2:2e

From Förberedande kurs i matematik 1

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m (Lösning 4.2:2e moved to Solution 4.2:2e: Robot: moved page)
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This exercise is somewhat of a trick question, because we don't need any trigonometry to solve it.
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<center> [[Image:4_2_2e.gif]] </center>
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Two angles are given in the triangle (the
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<math>\text{6}0^{\circ }</math>
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angle and the right-angle) and thus we can use the fact that the sum of all the angles in a triangle is
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<math>\text{18}0^{\circ }</math>,
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<math>v+60^{\circ }+90^{\circ }=180^{\circ }</math>
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which gives
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<math>v=180^{\circ }-60^{\circ }-90^{\circ }=30^{\circ }</math>

Revision as of 11:35, 28 September 2008

This exercise is somewhat of a trick question, because we don't need any trigonometry to solve it.

Two angles are given in the triangle (the 60 angle and the right-angle) and thus we can use the fact that the sum of all the angles in a triangle is 180,


v+60+90=180


which gives


v=180−60−90=30

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