Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution 2.2:6c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 2.2:6c moved to Solution 2.2:6c: Robot: moved page)
Line 1: Line 1:
 +
The point of intersection is that point which satisfies the equations of both lines
 +
 +
 +
<math>4x+5y+6=0</math>
 +
and
 +
<math>x=0</math>.
 +
 +
Substituting
 +
<math>4x+5y+6=0</math>
 +
into
 +
<math>x=0</math>
 +
gives
 +
 +
 +
<math>4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}</math>
 +
 +
 +
This gives the point of intersection as
 +
<math>\left( 0 \right.,\left. -\frac{6}{5} \right)</math>.
 +
 +
 +
{{NAVCONTENT_START}}
{{NAVCONTENT_START}}
-
<center> [[Image:2_2_6c.gif]] </center>
+
 
[[Image:2_2_6_c.gif|center]]
[[Image:2_2_6_c.gif|center]]
{{NAVCONTENT_STOP}}
{{NAVCONTENT_STOP}}

Revision as of 11:34, 18 September 2008

The point of intersection is that point which satisfies the equations of both lines


4x+5y+6=0 and x=0.

Substituting 4x+5y+6=0 into x=0 gives


40+5y+6=0  y=−56


This gives the point of intersection as 0−56 .


Retrieved from "http://wiki.math.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Solution_2.2:6c"