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Answer 1.1:2

From Förberedande kurs i matematik 1

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>(3-(7-4))(6-5)</math> |b) |width="50%" | <math>3-(((7-4)+6)-5)</math> |- |c) || <math>3\cdot(-7)-4\cdot(6-5)</math> |d) || <math>...)
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Revision as of 09:57, 20 March 2008

a) (3−(7−4))(6−5) b) 3−(((7−4)+6)−5)
c) 3(−7)−4(6−5) d) 3(−7)−(4+6)(−5)
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