Solution 1.1:1d

Just as in exercise c, we calculate the innermost bracket

3−(7−(4+6))−5=3−(7−10)−5

and work our way successively outwards,

=3−(7−10)−5

=3−(−3)−5.

All that remains is to combine the terms from left to right

=3−(−3)−5

=3+3−5

=6−5

=1.