Processing Math: Done
Solution 1.2:2c
From Förberedande kurs i matematik 1
We divide up the two numerators into the smallest possible integer factors,
6=2
2
314=2
7
The expression can thus be written as
2
3−12
7
Here, we see that the denominators have a factor
3
2
3
7
2
3−12
7=12
2
3
77−12
7
2
32
3
The lowest common denominator is