Solution 3.4:1a

From Förberedande kurs i matematik 2

(Difference between revisions)
Jump to: navigation, search
m (Lösning 3.4:1a moved to Solution 3.4:1a: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
The numerator can be factorized using the conjugate rule to give
-
<center> [[Image:3_4_1a.gif]] </center>
+
<math>x^{2}-1=\left( x+1 \right)\left( x-1 \right)</math>
-
{{NAVCONTENT_STOP}}
+
and then we see that the numerator and denominator have a common factor which we can eliminate
 +
 
 +
 
 +
<math>\frac{x^{2}-1}{x-1}=\frac{\left( x+1 \right)\left( x-1 \right)}{x-1}=x+1</math>

Revision as of 12:30, 26 October 2008

The numerator can be factorized using the conjugate rule to give \displaystyle x^{2}-1=\left( x+1 \right)\left( x-1 \right) and then we see that the numerator and denominator have a common factor which we can eliminate


\displaystyle \frac{x^{2}-1}{x-1}=\frac{\left( x+1 \right)\left( x-1 \right)}{x-1}=x+1

Retrieved from "http://wiki.math.se/wikis/2009/bridgecourse2-ImperialCollege/index.php/Solution_3.4:1a"