Ian: New page: $\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}$ $\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}$

Ian — Sat, 12 Sep 2009 16:28:14 GMT

New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>

Ny sida

<math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math>

<math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>

Answer 8.5a - Versionshistorik

Ian: New page: \mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j} \mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}

Ian: New page: $\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}$ $\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}$