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Lösning 5.1:2 - Versionshistorik
2026-04-08T07:31:05Z
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Louwah: Ny sida: a) <math>l = l_0 \sqrt{1-(v/c)^2} = 2800\, \textrm{m} \sqrt{1-(8{,}0\cdot 10^7\,\textrm{m/s}/c)^2} \approx 2700\, \textrm{m} </math> b)<math>\Delta t = \displaystyle\frac{2800\, \textrm{m}...
2017-12-13T10:56:59Z
<p>Ny sida: a) <math>l = l_0 \sqrt{1-(v/c)^2} = 2800\, \textrm{m} \sqrt{1-(8{,}0\cdot 10^7\,\textrm{m/s}/c)^2} \approx 2700\, \textrm{m} </math> b)<math>\Delta t = \displaystyle\frac{2800\, \textrm{m}...</p>
<p><b>Ny sida</b></p><div>a) <math>l = l_0 \sqrt{1-(v/c)^2} = 2800\, \textrm{m} \sqrt{1-(8{,}0\cdot 10^7\,\textrm{m/s}/c)^2} \approx 2700\, \textrm{m} </math><br />
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b)<math>\Delta t = \displaystyle\frac{2800\, \textrm{m}}{8{,}0\cdot 10^7\,\textrm{m/s}} = 3{,}5\, 10^{-5}\, \textrm{s}</math> <br />
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c)<math>\Delta t = \displaystyle\frac{l\, \textrm{m}}{8{,}0\cdot 10^7\,\textrm{m/s}} = 3,4\, 10^{-5}\, \textrm{s}</math></div>
Louwah