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Svar 2.2:7 - Versionshistorik
2026-04-08T02:44:31Z
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Louwah den 20 december 2017 kl. 10.50
2017-12-20T10:50:20Z
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<td colspan='2' style="background-color: white; color:black;">← Äldre version</td>
<td colspan='2' style="background-color: white; color:black;">Versionen från 20 december 2017 kl. 10.50</td>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">'''F'''</del><math>=<del style="color: red; font-weight: bold; text-decoration: none;">Fe_F</del>=<del style="color: red; font-weight: bold; text-decoration: none;">120N</del>\frac{(2,5)m-(0,3)m}{\sqrt{(2-0)^2+(5-3)^2}m}=120\frac{(2,2)}{\sqrt{8}}N=120\frac{(1,1)}{\sqrt{2}}N </math></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math> <ins style="color: red; font-weight: bold; text-decoration: none;">\mathbf{F} </ins>= <ins style="color: red; font-weight: bold; text-decoration: none;">F\mathbf{e}_F </ins>= <ins style="color: red; font-weight: bold; text-decoration: none;">120\, \textrm{N}\,\ </ins>\frac{(2,5)<ins style="color: red; font-weight: bold; text-decoration: none;">\,\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>-(0,3)<ins style="color: red; font-weight: bold; text-decoration: none;">\,\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>}{\sqrt{(2-0)^2+(5-3)^2}<ins style="color: red; font-weight: bold; text-decoration: none;">\,\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>} = 120\frac{(2,2)}{\sqrt{8}}<ins style="color: red; font-weight: bold; text-decoration: none;">\,\textrm{</ins>N<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins>= 120\frac{(1,1)}{\sqrt{2}}<ins style="color: red; font-weight: bold; text-decoration: none;">\, \textrm{</ins>N<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins></math></div></td></tr>
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Louwah
http://wiki.math.se/wikis/forberedandefysik/index.php?title=Svar_2.2:7&diff=1117&oldid=prev
Lena Chytraeus: Ny sida: '''F'''<math>=Fe_F=120N\frac{(2,5)m-(0,3)m}{\sqrt{(2-0)^2+(5-3)^2}m}=120\frac{(2,2)}{\sqrt{8}}N=120\frac{(1,1)}{\sqrt{2}}N </math>
2009-12-15T15:56:48Z
<p>Ny sida: '''F'''<math>=Fe_F=120N\frac{(2,5)m-(0,3)m}{\sqrt{(2-0)^2+(5-3)^2}m}=120\frac{(2,2)}{\sqrt{8}}N=120\frac{(1,1)}{\sqrt{2}}N </math></p>
<p><b>Ny sida</b></p><div>'''F'''<math>=Fe_F=120N\frac{(2,5)m-(0,3)m}{\sqrt{(2-0)^2+(5-3)^2}m}=120\frac{(2,2)}{\sqrt{8}}N=120\frac{(1,1)}{\sqrt{2}}N </math></div>
Lena Chytraeus