http://wiki.math.se/wikis/forberedandefysik/index.php?title=L%C3%B6sning_2.5:7&action=history Versionshistorik för denna sida på wikin sv MediaWiki 1.11.1 Wed, 08 Apr 2026 01:15:42 GMT http://wiki.math.se/wikis/forberedandefysik/index.php?title=L%C3%B6sning_2.5:7&diff=2766&oldid=prev <p></p> <table style="background-color: white; color:black;"> <col class='diff-marker' /> <col class='diff-content' /> <col class='diff-marker' /> <col class='diff-content' /> <tr> <td colspan='2' style="background-color: white; color:black;">← Äldre version</td> <td colspan='2' style="background-color: white; color:black;">Versionen från 20 december 2017 kl. 15.51</td> </tr> <tr><td colspan="2" class="diff-lineno">Rad 1:</td> <td colspan="2" class="diff-lineno">Rad 1:</td></tr> <tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">Varje kvadrat har sitt masscentrum mitt i kvadraten.&lt;br\&gt;</del></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>&lt;math&gt;<ins style="color: red; font-weight: bold; text-decoration: none;">\displaystyle \mathbf{r}_g </ins>= \frac{<ins style="color: red; font-weight: bold; text-decoration: none;">4\textrm{kg}</ins>(0,5;<ins style="color: red; font-weight: bold; text-decoration: none;">\,</ins>0,5)<ins style="color: red; font-weight: bold; text-decoration: none;">\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>+<ins style="color: red; font-weight: bold; text-decoration: none;">4\textrm{kg}</ins>(0,5;<ins style="color: red; font-weight: bold; text-decoration: none;">\,</ins>-0,5)<ins style="color: red; font-weight: bold; text-decoration: none;">\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>}{<ins style="color: red; font-weight: bold; text-decoration: none;">4\textrm{kg}</ins>+<ins style="color: red; font-weight: bold; text-decoration: none;">4\textrm{kg}</ins>} = \frac{4(1,0;<ins style="color: red; font-weight: bold; text-decoration: none;">\,</ins>0)}{8}<ins style="color: red; font-weight: bold; text-decoration: none;">\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins>=(0,5;<ins style="color: red; font-weight: bold; text-decoration: none;">\,</ins>0)<ins style="color: red; font-weight: bold; text-decoration: none;">\,\textrm{</ins>m<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins>&lt;/math&gt;</div></td></tr> <tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>&#160;</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div></div></td></tr> <tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>&#160;</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div></div></td></tr> <tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>&lt;math&gt;<del style="color: red; font-weight: bold; text-decoration: none;">r_g</del>=\frac{<del style="color: red; font-weight: bold; text-decoration: none;">4kg</del>(0,5;0,5)m+<del style="color: red; font-weight: bold; text-decoration: none;">4kg</del>(0,5;-0,5)m}{<del style="color: red; font-weight: bold; text-decoration: none;">4kg</del>+<del style="color: red; font-weight: bold; text-decoration: none;">4kg</del>}=\frac{4(1,0;0)}{8}m=(0,5;0)m &lt;/math&gt;</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div></div></td></tr> </table> Wed, 20 Dec 2017 15:51:41 GMT Louwah http://wiki.math.se/wikis/forberedandefysik/index.php/Diskussion:L%C3%B6sning_2.5:7 http://wiki.math.se/wikis/forberedandefysik/index.php?title=L%C3%B6sning_2.5:7&diff=1282&oldid=prev <p></p> <table style="background-color: white; color:black;"> <col class='diff-marker' /> <col class='diff-content' /> <col class='diff-marker' /> <col class='diff-content' /> <tr> <td colspan='2' style="background-color: white; color:black;">← Äldre version</td> <td colspan='2' style="background-color: white; color:black;">Versionen från 16 december 2009 kl. 15.32</td> </tr> <tr><td colspan="2" class="diff-lineno">Rad 1:</td> <td colspan="2" class="diff-lineno">Rad 1:</td></tr> <tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Varje kvadrat har sitt masscentrum mitt i kvadraten.&lt;br\&gt;</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Varje kvadrat har sitt masscentrum mitt i kvadraten.&lt;br\&gt;</div></td></tr> <tr><td colspan="2">&nbsp;</td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"></td></tr> <tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr> <tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>&lt;math&gt;r_g=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m}{4kg+4kg}=\frac{4(1,0;0)}{8}m=(0,5;0)m &lt;/math&gt;</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>&lt;math&gt;r_g=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m}{4kg+4kg}=\frac{4(1,0;0)}{8}m=(0,5;0)m &lt;/math&gt;</div></td></tr> </table> Wed, 16 Dec 2009 15:32:09 GMT Lena Chytraeus http://wiki.math.se/wikis/forberedandefysik/index.php/Diskussion:L%C3%B6sning_2.5:7 http://wiki.math.se/wikis/forberedandefysik/index.php?title=L%C3%B6sning_2.5:7&diff=1260&oldid=prev <p>Ny sida: Varje kvadrat har sitt masscentrum mitt i kvadraten.&lt;br\&gt; &lt;math&gt;r_g=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m}{4kg+4kg}=\frac{4(1,0;0)}{8}m=(0,5;0)m &lt;/math&gt;</p> <p><b>Ny sida</b></p><div>Varje kvadrat har sitt masscentrum mitt i kvadraten.&lt;br\&gt;<br /> <br /> &lt;math&gt;r_g=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m}{4kg+4kg}=\frac{4(1,0;0)}{8}m=(0,5;0)m &lt;/math&gt;</div> Wed, 16 Dec 2009 13:48:23 GMT Lena Chytraeus http://wiki.math.se/wikis/forberedandefysik/index.php/Diskussion:L%C3%B6sning_2.5:7