Louwah: Ny sida: $\gamma = \displaystyle\frac{l}{l'} = \displaystyle\frac{1{,}0 \textrm{ m}}{0{,}30 \textrm{ m}}$ $\Rightarrow v=c \sqrt{1-(1/\gamma)^2} \approx 0{,}95c_0 \textrm{ m/s}$
Louwah — Wed, 13 Dec 2017 10:54:32 GMT

Ny sida: <math> \gamma = \displaystyle\frac{l}{l'} = \displaystyle\frac{1{,}0 \textrm{ m}}{0{,}30 \textrm{ m}}</math> <math>\Rightarrow v=c \sqrt{1-(1/\gamma)^2} \approx 0{,}95c_0 \textrm{ m/s}</mat...

Ny sida
<math> \gamma = \displaystyle\frac{l}{l'} = \displaystyle\frac{1{,}0 \textrm{ m}}{0{,}30 \textrm{ m}}</math>
<math>\Rightarrow v=c \sqrt{1-(1/\gamma)^2} \approx 0{,}95c_0 \textrm{ m/s}</math>
<math>\Rightarrow v \approx 2{,}9\cdot 10^8 \textrm{ m/s}</math>

Lösning 5.1:1 - Versionshistorik