http://wiki.math.se/wikis/forberedandefysik/index.php?title=Svar_2.4:5&action=history Versionshistorik för denna sida på wikin sv MediaWiki 1.11.1 Wed, 08 Apr 2026 01:13:15 GMT http://wiki.math.se/wikis/forberedandefysik/index.php?title=Svar_2.4:5&diff=2745&oldid=prev <p></p> <table style="background-color: white; color:black;"> <col class='diff-marker' /> <col class='diff-content' /> <col class='diff-marker' /> <col class='diff-content' /> <tr> <td colspan='2' style="background-color: white; color:black;">← Äldre version</td> <td colspan='2' style="background-color: white; color:black;">Versionen från 20 december 2017 kl. 14.46</td> </tr> <tr><td colspan="2" class="diff-lineno">Rad 1:</td> <td colspan="2" class="diff-lineno">Rad 1:</td></tr> <tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Dela upp kraften i komposanter: &lt;math&gt;F=<del style="color: red; font-weight: bold; text-decoration: none;">100N</del>(\<del style="color: red; font-weight: bold; text-decoration: none;">cos45</del>^\circ <del style="color: red; font-weight: bold; text-decoration: none;">e_x</del>+\<del style="color: red; font-weight: bold; text-decoration: none;">sin45</del>^\circ <del style="color: red; font-weight: bold; text-decoration: none;">e_y</del>)=50\sqrt{2}N(<del style="color: red; font-weight: bold; text-decoration: none;">e_x</del>+<del style="color: red; font-weight: bold; text-decoration: none;">e_y</del>)&lt;/math&gt; Den första komposanten vrider runt negativa <del style="color: red; font-weight: bold; text-decoration: none;">&lt;math&gt;</del>z<del style="color: red; font-weight: bold; text-decoration: none;">&lt;/math&gt;</del>-axeln och har hävarmen <del style="color: red; font-weight: bold; text-decoration: none;">&lt;math&gt;</del>1<del style="color: red; font-weight: bold; text-decoration: none;">&lt;/math&gt; </del>m; den andra komposanten vrider runt positiva <del style="color: red; font-weight: bold; text-decoration: none;">&lt;math&gt;</del>z<del style="color: red; font-weight: bold; text-decoration: none;">&lt;/math&gt;</del>-axeln och har hävarmen <del style="color: red; font-weight: bold; text-decoration: none;">&lt;math&gt;</del>2<del style="color: red; font-weight: bold; text-decoration: none;">&lt;/math&gt; </del>m. Tillsammans blir då <del style="color: red; font-weight: bold; text-decoration: none;">'''M'''</del>&lt;math&gt;<del style="color: red; font-weight: bold; text-decoration: none;">_o</del>=–50\sqrt{2}N\cdot <del style="color: red; font-weight: bold; text-decoration: none;">1me_z</del>+50\sqrt{2}N\cdot <del style="color: red; font-weight: bold; text-decoration: none;">2me_z</del>=50\sqrt{2}<del style="color: red; font-weight: bold; text-decoration: none;">e_zNm</del>&lt;/math&gt;.</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Dela upp kraften i komposanter: &lt;math&gt; <ins style="color: red; font-weight: bold; text-decoration: none;">\mathbf{</ins>F<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins>= <ins style="color: red; font-weight: bold; text-decoration: none;">100\, \textrm{N}</ins>(\<ins style="color: red; font-weight: bold; text-decoration: none;">cos{45</ins>^\circ<ins style="color: red; font-weight: bold; text-decoration: none;">} \mathbf{e}_x </ins>+ \<ins style="color: red; font-weight: bold; text-decoration: none;">sin{45</ins>^\circ<ins style="color: red; font-weight: bold; text-decoration: none;">}\, \mathbf{e}_y</ins>) = 50\sqrt{2}<ins style="color: red; font-weight: bold; text-decoration: none;">\, </ins>N (<ins style="color: red; font-weight: bold; text-decoration: none;">\mathbf{e}_x </ins>+ <ins style="color: red; font-weight: bold; text-decoration: none;">\mathbf{e}_y</ins>) &lt;/math&gt; Den första komposanten vrider runt negativa z-axeln och har hävarmen 1 m; den andra komposanten vrider runt positiva z-axeln och har hävarmen 2 m. Tillsammans blir då &lt;math&gt;<ins style="color: red; font-weight: bold; text-decoration: none;">\mathbf{M}_O </ins>= –50\sqrt{2}<ins style="color: red; font-weight: bold; text-decoration: none;">\, \textrm{</ins>N<ins style="color: red; font-weight: bold; text-decoration: none;">}\, </ins>\cdot <ins style="color: red; font-weight: bold; text-decoration: none;">1\, \textrm{m}\, \mathbf{e}_z </ins>+ 50\sqrt{2}<ins style="color: red; font-weight: bold; text-decoration: none;">\, \textrm{</ins>N<ins style="color: red; font-weight: bold; text-decoration: none;">} </ins>\cdot <ins style="color: red; font-weight: bold; text-decoration: none;">2\, \textrm{m}\, \mathbf{e}_z </ins>= 50\sqrt{2}<ins style="color: red; font-weight: bold; text-decoration: none;">\, \mathbf{e}_z\, \textrm{Nm} </ins>&lt;/math&gt;.</div></td></tr> </table> Wed, 20 Dec 2017 14:46:37 GMT Louwah http://wiki.math.se/wikis/forberedandefysik/index.php/Diskussion:Svar_2.4:5 http://wiki.math.se/wikis/forberedandefysik/index.php?title=Svar_2.4:5&diff=1204&oldid=prev <p>Ny sida: Dela upp kraften i komposanter: &lt;math&gt;F=100N(\cos45^\circ e_x+\sin45^\circ e_y)=50\sqrt{2}N(e_x+e_y)&lt;/math&gt; Den första komposanten vrider runt negativa &lt;math&gt;z&lt;/math&gt;-axeln och har hävarm...</p> <p><b>Ny sida</b></p><div>Dela upp kraften i komposanter: &lt;math&gt;F=100N(\cos45^\circ e_x+\sin45^\circ e_y)=50\sqrt{2}N(e_x+e_y)&lt;/math&gt; Den första komposanten vrider runt negativa &lt;math&gt;z&lt;/math&gt;-axeln och har hävarmen &lt;math&gt;1&lt;/math&gt; m; den andra komposanten vrider runt positiva &lt;math&gt;z&lt;/math&gt;-axeln och har hävarmen &lt;math&gt;2&lt;/math&gt; m. Tillsammans blir då '''M'''&lt;math&gt;_o=–50\sqrt{2}N\cdot 1me_z+50\sqrt{2}N\cdot 2me_z=50\sqrt{2}e_zNm&lt;/math&gt;.</div> Wed, 16 Dec 2009 12:25:31 GMT Lena Chytraeus http://wiki.math.se/wikis/forberedandefysik/index.php/Diskussion:Svar_2.4:5