Processing Math: Done
Solution 1.2:2d
From Förberedande kurs i matematik 1
If we divide up the denominators into their smallest possible integer factors,
![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
the expression can be written as
![]() ![]() ![]() ![]() |
and then we see that the denominators have 5
![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
The lowest common denominator is 225.