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Solution 2.1:1g

From Förberedande kurs i matematik 1

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The expression in the exercise is of the form (a−b)2, where a=y2 and b=3x2. With the help of the squaring rule (a−b)2=a2−2ab+b2, we have

(y2−3x3)2=(y2)2−2y23x3+(3x3)2=y22−6x3y2+32x32=y4−6x3y2+9x6=9x6−6x3y2+y4.
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