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Solution 2.2:6d

From Förberedande kurs i matematik 1

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At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,

x+y+1=0andx=12.

We obtain the solution to this system of equations by substituting x=12 into the first equation

12+y+1=0y=−13,

which gives us the point of intersection as (12,-13).


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