By writing 0.027 as 2710−3, where 27=333=33 and 10−3=(10−1)3=0.13 we see that
where we have used 3a3=a313=a331=a1=a.
10−333=33
30.027=
32710−3=327310−3=33330.13=30.1=0.3,3a3=
a3
1
3=a3
31=a1=a. 