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Övningar 3.4

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Versionen från 16 juli 2007 kl. 08.10 (redigera)
KTH.SE:u1zpa8nw (Diskussion | bidrag)
(Ny sida: __NOTOC__ ==&Ouml;vning 3.4:1== <div class="ovning"> L&ouml;s ekvationerna <table width="100%" cellspacing="10px"> <tr align="left"> <td class="ntext">a)</td> <td class="ntext" width="33%">...)
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Versionen från 16 juli 2007 kl. 11.31 (redigera) (ogör)
KTH.SE:u1zpa8nw (Diskussion | bidrag)

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Rad 1: Rad 1:
__NOTOC__ __NOTOC__
-==&Ouml;vning 3.4:1==+'''&Ouml;vning 3.4:1'''
-<div class="ovning">+<div class="ovning" style="margin-top:-20px; margin-bottom:-5px;">
L&ouml;s ekvationerna L&ouml;s ekvationerna
-<table width="100%" cellspacing="10px">+<table width="100%">
<tr align="left"> <tr align="left">
-<td class="ntext">a)</td>+<td class="ntext">a)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">e^x=13</td> <td class="ntext" width="33%">e^x=13</td>
-<td class="ntext">b)</td>+<td class="ntext">b)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">13e^x=2\cdot3^{-x}</td> <td class="ntext" width="33%">13e^x=2\cdot3^{-x}</td>
-<td class="ntext">c)</td>+<td class="ntext">c)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">3e^x=7\cdot2^x</td> <td class="ntext" width="33%">3e^x=7\cdot2^x</td>
<tr><td height="5px"/></tr> <tr><td height="5px"/></tr>
Rad 16: Rad 16:
</div> </div>
-==&Ouml;vning 3.4:2==+'''&Ouml;vning 3.4:2'''
-<div class="ovning">+<div class="ovning" style="margin-top:-20px; margin-bottom:-5px;">
L&ouml;s ekvationerna L&ouml;s ekvationerna
-<table width="100%" cellspacing="10px">+<table width="100%">
<tr align="left"> <tr align="left">
-<td class="ntext">a)</td>+<td class="ntext">a)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">2^{\scriptstyle x^2-2}=1</td> <td class="ntext" width="33%">2^{\scriptstyle x^2-2}=1</td>
-<td class="ntext">b)</td>+<td class="ntext">b)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">e^{2x}+e^x=4</td> <td class="ntext" width="33%">e^{2x}+e^x=4</td>
-<td class="ntext">c)</td>+<td class="ntext">c)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="33%">3e^{x^2}=2^x</td> <td class="ntext" width="33%">3e^{x^2}=2^x</td>
</tr> </tr>
Rad 32: Rad 32:
</div> </div>
-==&Ouml;vning 3.4:3==+'''&Ouml;vning 3.4:3'''
-<div class="ovning">+<div class="ovning" style="margin-top:-20px; margin-bottom:-5px;">
L&ouml;s ekvationerna L&ouml;s ekvationerna
-<table width="100%" cellspacing="10px">+<table width="100%">
<tr align="left"> <tr align="left">
-<td class="ntext">a)</td>+<td class="ntext">a)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="50%">2^{-x^2}=2e^{2x}</td> <td class="ntext" width="50%">2^{-x^2}=2e^{2x}</td>
-<td class="ntext">b)</td>+<td class="ntext">b)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="50%">\ln{(x^2+3x)}=\ln{(3x^2-2x)}</td> <td class="ntext" width="50%">\ln{(x^2+3x)}=\ln{(3x^2-2x)}</td>
</tr> </tr>
<tr align="left"> <tr align="left">
-<td class="ntext">c)</td>+<td class="ntext">c)&nbsp;&nbsp;&nbsp;</td>
<td class="ntext" width="50%">\ln{x}+\ln{(x+4)}=\ln{(2x+3)}</td> <td class="ntext" width="50%">\ln{x}+\ln{(x+4)}=\ln{(2x+3)}</td>
</tr> </tr>

Versionen från 16 juli 2007 kl. 11.31

Övning 3.4:1

Lös ekvationerna

a)    e^x=13 b)    13e^x=2\cdot3^{-x} c)    3e^x=7\cdot2^x

Övning 3.4:2

Lös ekvationerna

a)    2^{\scriptstyle x^2-2}=1 b)    e^{2x}+e^x=4 c)    3e^{x^2}=2^x

Övning 3.4:3

Lös ekvationerna

a)    2^{-x^2}=2e^{2x} b)    \ln{(x^2+3x)}=\ln{(3x^2-2x)}
c)    \ln{x}+\ln{(x+4)}=\ln{(2x+3)}
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