Övningar 3.4
Sommarmatte 1
(Skillnad mellan versioner)
| Versionen från 16 juli 2007 kl. 11.31 (redigera) KTH.SE:u1zpa8nw (Diskussion | bidrag) ← Gå till föregående ändring |
Nuvarande version (17 juli 2007 kl. 09.43) (redigera) (ogör) KTH.SE:u1zpa8nw (Diskussion | bidrag) |
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| (2 mellanliggande versioner visas inte.) | |||
| Rad 22: | Rad 22: | ||
| <tr align="left"> | <tr align="left"> | ||
| <td class="ntext">a) </td> | <td class="ntext">a) </td> | ||
| - | <td class="ntext" width="33%">$2^{\scriptstyle x^2-2}=1$</td> | + | <td class="ntext" width="33%">$2^{\scriptstyle x^{\scriptstyle2}-2}=1$</td> |
| <td class="ntext">b) </td> | <td class="ntext">b) </td> | ||
| <td class="ntext" width="33%">$e^{2x}+e^x=4$</td> | <td class="ntext" width="33%">$e^{2x}+e^x=4$</td> | ||
| <td class="ntext">c) </td> | <td class="ntext">c) </td> | ||
| - | <td class="ntext" width="33%">$3e^{x^2}=2^x$</td> | + | <td class="ntext" width="33%">$3e^{x^{\scriptstyle2}}=2^x$</td> |
| </tr> | </tr> | ||
| <tr><td height="5px"/></tr> | <tr><td height="5px"/></tr> | ||
| Rad 38: | Rad 38: | ||
| <tr align="left"> | <tr align="left"> | ||
| <td class="ntext">a) </td> | <td class="ntext">a) </td> | ||
| - | <td class="ntext" width="50%">$2^{-x^2}=2e^{2x}$</td> | + | <td class="ntext" width="50%">$2^{-x^{\scriptstyle2}}=2e^{2x}$</td> |
| <td class="ntext">b) </td> | <td class="ntext">b) </td> | ||
| <td class="ntext" width="50%">$\ln{(x^2+3x)}=\ln{(3x^2-2x)}$</td> | <td class="ntext" width="50%">$\ln{(x^2+3x)}=\ln{(3x^2-2x)}$</td> | ||
| Rad 49: | Rad 49: | ||
| </table> | </table> | ||
| </div> | </div> | ||
| + | <br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br> | ||
Nuvarande version
Övning 3.4:1
Lös ekvationerna
| a) | $e^x=13$ | b) | $13e^x=2\cdot3^{-x}$ | c) | $3e^x=7\cdot2^x$ |
Övning 3.4:2
Lös ekvationerna
| a) | $2^{\scriptstyle x^{\scriptstyle2}-2}=1$ | b) | $e^{2x}+e^x=4$ | c) | $3e^{x^{\scriptstyle2}}=2^x$ |
Övning 3.4:3
Lös ekvationerna
| a) | $2^{-x^{\scriptstyle2}}=2e^{2x}$ | b) | $\ln{(x^2+3x)}=\ln{(3x^2-2x)}$ |
| c) | $\ln{x}+\ln{(x+4)}=\ln{(2x+3)}$ | ||
