Övningar 3.4
Sommarmatte 1
(Skillnad mellan versioner)
| Versionen från 16 juli 2007 kl. 08.10 (redigera) KTH.SE:u1zpa8nw (Diskussion | bidrag) (Ny sida: __NOTOC__ ==Övning 3.4:1== <div class="ovning"> Lös ekvationerna <table width="100%" cellspacing="10px"> <tr align="left"> <td class="ntext">a)</td> <td class="ntext" width="33%">...) ← Gå till föregående ändring |
Nuvarande version (17 juli 2007 kl. 09.43) (redigera) (ogör) KTH.SE:u1zpa8nw (Diskussion | bidrag) |
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| (3 mellanliggande versioner visas inte.) | |||
| Rad 1: | Rad 1: | ||
| __NOTOC__ | __NOTOC__ | ||
| - | ==Övning 3.4:1== | + | '''Övning 3.4:1''' |
| - | <div class="ovning"> | + | <div class="ovning" style="margin-top:-20px; margin-bottom:-5px;"> |
| Lös ekvationerna | Lös ekvationerna | ||
| - | <table width="100%" cellspacing="10px"> | + | <table width="100%"> |
| <tr align="left"> | <tr align="left"> | ||
| - | <td class="ntext">a)</td> | + | <td class="ntext">a) </td> |
| <td class="ntext" width="33%">e^x=13</td> | <td class="ntext" width="33%">e^x=13</td> | ||
| - | <td class="ntext">b)</td> | + | <td class="ntext">b) </td> |
| <td class="ntext" width="33%">13e^x=2\cdot3^{-x}</td> | <td class="ntext" width="33%">13e^x=2\cdot3^{-x}</td> | ||
| - | <td class="ntext">c)</td> | + | <td class="ntext">c) </td> |
| <td class="ntext" width="33%">3e^x=7\cdot2^x</td> | <td class="ntext" width="33%">3e^x=7\cdot2^x</td> | ||
| <tr><td height="5px"/></tr> | <tr><td height="5px"/></tr> | ||
| Rad 16: | Rad 16: | ||
| </div> | </div> | ||
| - | ==Övning 3.4:2== | + | '''Övning 3.4:2''' |
| - | <div class="ovning"> | + | <div class="ovning" style="margin-top:-20px; margin-bottom:-5px;"> |
| Lös ekvationerna | Lös ekvationerna | ||
| - | <table width="100%" cellspacing="10px"> | + | <table width="100%"> |
| <tr align="left"> | <tr align="left"> | ||
| - | <td class="ntext">a)</td> | + | <td class="ntext">a) </td> |
| - | <td class="ntext" width="33%">$2^{\scriptstyle x^2-2}=1$</td> | + | <td class="ntext" width="33%">$2^{\scriptstyle x^{\scriptstyle2}-2}=1$</td> |
| - | <td class="ntext">b)</td> | + | <td class="ntext">b) </td> |
| <td class="ntext" width="33%">e^{2x}+e^x=4</td> | <td class="ntext" width="33%">e^{2x}+e^x=4</td> | ||
| - | <td class="ntext">c)</td> | + | <td class="ntext">c) </td> |
| - | <td class="ntext" width="33%">$3e^{x^2}=2^x$</td> | + | <td class="ntext" width="33%">$3e^{x^{\scriptstyle2}}=2^x$</td> |
| </tr> | </tr> | ||
| <tr><td height="5px"/></tr> | <tr><td height="5px"/></tr> | ||
| Rad 32: | Rad 32: | ||
| </div> | </div> | ||
| - | ==Övning 3.4:3== | + | '''Övning 3.4:3''' |
| - | <div class="ovning"> | + | <div class="ovning" style="margin-top:-20px; margin-bottom:-5px;"> |
| Lös ekvationerna | Lös ekvationerna | ||
| - | <table width="100%" cellspacing="10px"> | + | <table width="100%"> |
| <tr align="left"> | <tr align="left"> | ||
| - | <td class="ntext">a)</td> | + | <td class="ntext">a) </td> |
| - | <td class="ntext" width="50%">$2^{-x^2}=2e^{2x}$</td> | + | <td class="ntext" width="50%">$2^{-x^{\scriptstyle2}}=2e^{2x}$</td> |
| - | <td class="ntext">b)</td> | + | <td class="ntext">b) </td> |
| <td class="ntext" width="50%">\ln{(x^2+3x)}=\ln{(3x^2-2x)}</td> | <td class="ntext" width="50%">\ln{(x^2+3x)}=\ln{(3x^2-2x)}</td> | ||
| </tr> | </tr> | ||
| <tr align="left"> | <tr align="left"> | ||
| - | <td class="ntext">c)</td> | + | <td class="ntext">c) </td> |
| <td class="ntext" width="50%">\ln{x}+\ln{(x+4)}=\ln{(2x+3)}</td> | <td class="ntext" width="50%">\ln{x}+\ln{(x+4)}=\ln{(2x+3)}</td> | ||
| </tr> | </tr> | ||
| Rad 49: | Rad 49: | ||
| </table> | </table> | ||
| </div> | </div> | ||
| + | <br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br><br> | ||
Nuvarande version
Övning 3.4:1
Lös ekvationerna
| a) | e^x=13 | b) | 13e^x=2\cdot3^{-x} | c) | 3e^x=7\cdot2^x |
Övning 3.4:2
Lös ekvationerna
| a) | 2^{\scriptstyle x^{\scriptstyle2}-2}=1 | b) | e^{2x}+e^x=4 | c) | 3e^{x^{\scriptstyle2}}=2^x |
Övning 3.4:3
Lös ekvationerna
| a) | 2^{-x^{\scriptstyle2}}=2e^{2x} | b) | \ln{(x^2+3x)}=\ln{(3x^2-2x)} |
| c) | \ln{x}+\ln{(x+4)}=\ln{(2x+3)} | ||
