Svar 1.1:2
Förberedande kurs i matematik 2
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>f'(x)=2x-3</math> |b) |width="33%"| <math>f'(x)=-\sin x -\cos x</math> |c) |width="33%"| <math>f'(x)=e^x-\displaystyle\frac{1}{x}...) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>f'(x)=2x-3</math> |b) |width="33%"| <math>f'(x)=-\sin x -\cos x</math> |c) |width="33%"| <math>f'(x)=e^x-\displaystyle\frac{1}{x}...) |
Nuvarande version
| a) | \displaystyle f'(x)=2x-3 | b) | \displaystyle f'(x)=-\sin x -\cos x | c) | \displaystyle f'(x)=e^x-\displaystyle\frac{1}{x} |
| d) | \displaystyle f'(x)=\displaystyle\frac{1}{2}x^{-1/2}=\frac{1}{2\sqrt x} | e) | \displaystyle f'(x)=4x(x^2-1) | f) | \displaystyle f'(x)=-\sin \left(x+\frac{\pi}{3}\right) |
