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Lösning 2.5:8

FörberedandeFysik

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(Ny sida: <math>r_G=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m-1kg(0,75;-0,75)m}{4kg+4kg-1kg}</math> <br\> <math>=\frac{(3,25;0,75)}{7}m=(0,46;0,11)m</math>)
Rad 1: Rad 1:
<math>r_G=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m-1kg(0,75;-0,75)m}{4kg+4kg-1kg}</math> <br\>
<math>r_G=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m-1kg(0,75;-0,75)m}{4kg+4kg-1kg}</math> <br\>
 +
<math>=\frac{(3,25;0,75)}{7}m=(0,46;0,11)m</math>
<math>=\frac{(3,25;0,75)}{7}m=(0,46;0,11)m</math>

Versionen från 16 december 2009 kl. 15.34

rG=4kg+4kg1kg4kg(05;05)m+4kg(05;05)m1kg(075;075)m


=7(325;075)m=(046;011)m