Lösning 2.5:3
FörberedandeFysik
(Skillnad mellan versioner)
(Ny sida: <math>r_g=\frac{200g(1,1)m+100g(2,-1)m}{200g+100g}=\frac{(400,100)}{300}m=\frac{(4,1)}{3}m </math>) |
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Rad 1: | Rad 1: | ||
- | <math>r_g=\frac{ | + | <math>\displaystyle \mathbf{r_g} = \frac{200\textrm{g}(1,1)\textrm{m} + 100\textrm{g}(2,-1)\textrm{m}}{200\textrm{g}+100\textrm{g}} = \frac{(400,100)}{300}\textrm{m} = \frac{(4,1)}{3}\textrm{m} </math> |
Nuvarande version
\displaystyle \displaystyle \mathbf{r_g} = \frac{200\textrm{g}(1,1)\textrm{m} + 100\textrm{g}(2,-1)\textrm{m}}{200\textrm{g}+100\textrm{g}} = \frac{(400,100)}{300}\textrm{m} = \frac{(4,1)}{3}\textrm{m}