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jsMath

Lösning 2.5:8

FörberedandeFysik

(Skillnad mellan versioner)
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Rad 1: Rad 1:
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<math>r_G=\frac{4kg(0,5;0,5)m+4kg(0,5;-0,5)m-1kg(0,75;-0,75)m}{4kg+4kg-1kg}</math> <br\>
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<math>\displaystyle \mathbf{r_G} = \frac{4\textrm{kg}(0,5;\,0,5)\textrm{m}+4\textrm{kg}(0,5;\,-0,5)\textrm{m}-1\textrm{kg}(0,75;\,-0,75)\textrm{m}}{4\, \textrm{kg} + 4\,\textrm{kg} - 1\,\textrm{kg}} </math>
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<math>\displaystyle = \frac{(3,25;\,0,75)}{7}\textrm{m} = (0,46;\,0,11)\,\textrm{m} </math> </math>
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<math>=\frac{(3,25;0,75)}{7}m=(0,46;0,11)m</math>
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Versionen från 20 december 2017 kl. 15.53

rG=4kg+4kg1kg4kg(05;05)m+4kg(05;05)m1kg(075;075)m

=7(325;075)m=(046;011)m </math>