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Svar 2.2:7

(Skillnad mellan versioner)

Lena Chytraeus (Diskussion | bidrag)
(Ny sida: '''F'''<math>=Fe_F=120N\frac{(2,5)m-(0,3)m}{\sqrt{(2-0)^2+(5-3)^2}m}=120\frac{(2,2)}{\sqrt{8}}N=120\frac{(1,1)}{\sqrt{2}}N </math>)
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Versionen från 15 december 2009 kl. 15.56

F=FeF=120N(25)m−(03)m(2−0)2+(5−3)2m=1208(22)N=1202(11)N