Lösning 2.5:4
FörberedandeFysik
(Skillnad mellan versioner)
(Ny sida: <math>r_g=\frac{1kg(3,5)m+2kg(-4,6)+4kg(3,-6)m}{1kg+2kg+4kg}=\frac{(7,-7)}{7}m=(1,-1)m </math>) |
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Rad 1: | Rad 1: | ||
- | <math> | + | <math>\displaystyle \mathbf{r}_g = \frac{1\textrm{kg}(3,5)\textrm{m} + 2\textrm{kg}(-4,6) + 4\textrm{kg}(3,-6)\textrm{m}}{1\textrm{kg}+2\textrm{kg}+4\textrm{kg}} = \frac{(7,-7)}{7}\textrm{m} = (1,-1)\textrm{m} </math> |
Nuvarande version
\displaystyle \displaystyle \mathbf{r}_g = \frac{1\textrm{kg}(3,5)\textrm{m} + 2\textrm{kg}(-4,6) + 4\textrm{kg}(3,-6)\textrm{m}}{1\textrm{kg}+2\textrm{kg}+4\textrm{kg}} = \frac{(7,-7)}{7}\textrm{m} = (1,-1)\textrm{m}