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Lösning 2.6:9

FörberedandeFysik

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l=10m; mg=393N;

cos=35; sin=45


Momentjämvikt kring kontaktpunkten mellan stången och golvet ger:

NA5lmg3lcos=0

NA=53mgcos=925mg=141N


Kraftjämvikt horisontellt ger:

f=NAsin=925mgsin=14154=113N


Kraftjämvikt i vertikal led ger:

Nmg+NAcos=0

N=mgNAcos=mg925mg53=98125mg=308N

=fN=308N113N=037