\displaystyle \displaystyle (3-2i)(4+i-(6-2i)) = (3-2i)(-2+3i)=
\displaystyle \displaystyle =(3\cdot (-2) + 3 \cdot 3i -2i\cdot(-2) -2i\cdot 3i = -6 +9i + 4i +6=
\displaystyle \displaystyle =13i
