2.2 Övningar
Sommarmatte 1
(Skillnad mellan versioner)
Versionen från 28 april 2007 kl. 14.28 (redigera) Annagf (Diskussion | bidrag) (→Övning 2.2:1) ← Gå till föregående ändring |
Versionen från 28 april 2007 kl. 14.30 (redigera) (ogör) Annagf (Diskussion | bidrag) (→Övning 2.2:1) Gå till nästa ändring → |
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Rad 2: | Rad 2: | ||
<div class="ovning"> | <div class="ovning"> | ||
Lös ekvationerna | Lös ekvationerna | ||
- | <table width="100%" cellspacing="10px"> | + | <table width="100%" cellspacing="10px"> |
- | <tr align="left"> | + | <tr align="left"> |
- | <td class="ntext">a)</td> | + | <td class="ntext">a)</td> |
- | <td class="ntext"> $\displaystyle\{x}-\displaystyle\frac{x+2}{9}=\displaystyle\frac{1}{2}$</td> | + | <td class="ntext"> \displaystyle\{x}-{2}</td> |
- | <td class="ntext">$\textrm{b) }$</td> | + | <td class="ntext">b)</td> |
- | <td class="ntext">\displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2</td> | + | <td class="ntext">\displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2</td> |
- | </tr> | + | </tr> |
- | <tr><td height="5px"/></tr> | + | <tr><td height="5px"/></tr> |
- | <tr align="left"> | + | <tr align="left"> |
- | <td class="ntext">$\textrm{c) }$</td> | + | <td class="ntext">c)</td> |
- | <td class="ntext">(x+3)^2-(x-5)^2=6x+4</td> | + | <td class="ntext">(x+3)^2-(x-5)^2=6x+4</td> |
- | <td class="ntext">$\textrm{d) }$</td> | + | <td class="ntext">d)</td> |
- | <td class="ntext">(x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2</td> | + | <td class="ntext">(x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2</td> |
- | </tr> | + | </tr> |
- | <tr><td height="5px"/></tr> | + | <tr><td height="5px"/></tr> |
- | <tr align="left"> | + | </table> |
- | <td class="ntext">\textrm{e) }</td> | + | |
- | <td class="ntext"> \displaystyle\frac{x+3}{x-3}-\displaystyle\frac{x+5}{x-2}=0</td> | + | |
- | <td class="ntext">\textrm{f) }</td> | + | |
- | <td class="ntext">\displaystyle\frac{4x}{4x-7}-\displaystyle\frac{1}{2x-3}=1</td> | + | |
- | </tr> | + | |
- | <tr><td height="5px"/></tr> | + | |
- | </table> | + | |
</div> | </div> | ||
Versionen från 28 april 2007 kl. 14.30
Övning 2.2:1
Lös ekvationerna
a) | \displaystyle\{x}-{2} | b) | \displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2 |
c) | (x+3)^2-(x-5)^2=6x+4 | d) | (x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2 |
Facit
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