2.2 Övningar

Sommarmatte 1

(Skillnad mellan versioner)
Hoppa till: navigering, sök
Versionen från 28 april 2007 kl. 15.04 (redigera)
Annagf (Diskussion | bidrag)
(Övning 2.2:2)
← Gå till föregående ändring
Versionen från 28 april 2007 kl. 15.11 (redigera) (ogör)
Annagf (Diskussion | bidrag)
(Övning 2.2:2)
Gå till nästa ändring →
Rad 77: Rad 77:
<table width="100%" cellspacing="10px"> <table width="100%" cellspacing="10px">
<tr align="left"> <tr align="left">
-<td class="ntext">$\textrm{a) }$</td>+<td class="ntext">a)</td>
<td class="ntext"> $\displaystyle\frac{5x}{6}-\displaystyle\frac{x+2}{9}=\displaystyle\frac{1}{2}$</td> <td class="ntext"> $\displaystyle\frac{5x}{6}-\displaystyle\frac{x+2}{9}=\displaystyle\frac{1}{2}$</td>
-<td class="ntext">$\textrm{b) }$</td>+<td class="ntext">b)</td>
<td class="ntext">$\displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2$</td> <td class="ntext">$\displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2$</td>
</tr> </tr>
<tr><td height="5px"/></tr> <tr><td height="5px"/></tr>
<tr align="left"> <tr align="left">
-<td class="ntext">$\textrm{c) }$</td>+<td class="ntext">c) </td>
<td class="ntext">$(x+3)^2-(x-5)^2=6x+4$</td> <td class="ntext">$(x+3)^2-(x-5)^2=6x+4$</td>
-<td class="ntext">$\textrm{d) }$</td>+<td class="ntext">d) </td>
<td class="ntext">$(x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2$</td> <td class="ntext">$(x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2$</td>
</tr> </tr>
Rad 100: Rad 100:
<table width="100%" cellspacing="10px"> <table width="100%" cellspacing="10px">
<tr align="left"> <tr align="left">
-<td class="ntext">$\textrm{a) }$</td>+<td class="ntext">a) </td>
<td class="ntext"> $x=1$</td> <td class="ntext"> $x=1$</td>
-<td class="ntext">$\textrm{b) }$</td>+<td class="ntext">b) </td>
<td class="ntext">$x=\displaystyle\frac{5}{3}$</td> <td class="ntext">$x=\displaystyle\frac{5}{3}$</td>
</tr> </tr>
<tr><td height="5px"/></tr> <tr><td height="5px"/></tr>
<tr align="left"> <tr align="left">
-<td class="ntext">$\textrm{c) }$</td>+<td class="ntext">c) </td>
<td class="ntext">$x=2$</td> <td class="ntext">$x=2$</td>
-<td class="ntext">$\textrm{d) }$</td>+<td class="ntext">d) </td>
<td class="ntext">$x=-2$</td> <td class="ntext">$x=-2$</td>
</tr> </tr>

Versionen från 28 april 2007 kl. 15.11

Övning 2.2:1

Lös ekvationerna

a) $x-2=-1$ b) $2x+1=13$
c) $\frac{1}{3}x-1=x$ d) $5x+7=2x-6$

Övning 2.2:2

Lös ekvationerna

a) $\displaystyle\frac{5x}{6}-\displaystyle\frac{x+2}{9}=\displaystyle\frac{1}{2}$ b) $\displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2$
c) $(x+3)^2-(x-5)^2=6x+4$ d) $(x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2$

Övning 2.2:3

Personliga verktyg