Processing Math: Done
Solution 2.3:1b
From Förberedande kurs i matematik 1
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- | {{ | + | When we complete the square, it is only the first two terms, |
- | < | + | <math>x^{2}+2x</math> |
- | {{ | + | , that are involved. The general |
+ | formula for completing the square states that | ||
+ | <math>x^{2}+ax</math> | ||
+ | equals | ||
+ | |||
+ | |||
+ | <math>\left( x+\frac{a}{2} \right)^{2}-\left( \frac{a}{2} \right)^{2}</math> | ||
+ | |||
+ | |||
+ | Note how the coefficient | ||
+ | <math>a</math> | ||
+ | in front of the | ||
+ | <math>x</math> | ||
+ | turns up halved in two places. | ||
+ | |||
+ | If we use this formula, we obtain | ||
+ | |||
+ | |||
+ | <math>x^{2}+2x=\left( x+\frac{2}{2} \right)^{2}-\left( \frac{2}{2} \right)^{2}=\left( x+1 \right)^{2}-1</math> | ||
+ | |||
+ | |||
+ | and if we subtract the last " | ||
+ | <math>1</math> | ||
+ | " , we obtain | ||
+ | |||
+ | |||
+ | <math>x^{2}+2x-1=\left( x+1 \right)^{2}-1-1=\left( x+1 \right)^{2}-2</math> | ||
+ | |||
+ | |||
+ | To be completely certain that we have used the correct formula, we can expand the quadratic on the right-hand side, | ||
+ | |||
+ | |||
+ | <math>\left( x+1 \right)^{2}-2=x^{2}+2x+1-2=x^{2}+2x-1</math> | ||
+ | |||
+ | |||
+ | and see that the relation really holds. |
Revision as of 10:11, 12 September 2008
When we complete the square, it is only the first two terms,
x+2a
2−
2a
2
Note how the coefficient
If we use this formula, we obtain
x+22
2−
22
2=
x+1
2−1
and if we subtract the last "
x+1
2−1−1=
x+1
2−2
To be completely certain that we have used the correct formula, we can expand the quadratic on the right-hand side,
x+1
2−2=x2+2x+1−2=x2+2x−1
and see that the relation really holds.