Processing Math: Done
Solution 1.1:1b
From Förberedande kurs i matematik 1
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- | + | We start by working out the expressions inside the brackets, | |
:<math>3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,} = 3-\bbox[#FFEEAA;,1.5pt]{\,3\,}+\bbox[#FFEEAA;,1.5pt]{\,1\,}</math>. | :<math>3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,} = 3-\bbox[#FFEEAA;,1.5pt]{\,3\,}+\bbox[#FFEEAA;,1.5pt]{\,1\,}</math>. | ||
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- | + | Then, all we have to do is to combine the numbers | |
:<math>\phantom{3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}}{} = \firstcbox{#FFEEAA;}{\,3-3\,}{0}+1</math> | :<math>\phantom{3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}+\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}}{} = \firstcbox{#FFEEAA;}{\,3-3\,}{0}+1</math> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} |
Current revision
We start by working out the expressions inside the brackets,
3−(7−4)+(6−5)=3−3+1 .
Then, all we have to do is to combine the numbers
=3−3+1
=0+1
=1.