Processing Math: Done
Solution 1.1:1c
From Förberedande kurs i matematik 1
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- | + | The brackets indicate in which order the expression is to be calculated, and we start by | |
+ | calculating the inner bracket. | ||
:<math>3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5) = 3-(7-\bbox[#FFEEAA;,1.5pt]{\,10\,}-5)</math>. | :<math>3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5) = 3-(7-\bbox[#FFEEAA;,1.5pt]{\,10\,}-5)</math>. | ||
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- | + | Then, we calculate the next bracket. | |
:<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3-\firstcbox{#FFEEAA;}{\,(7-10-5)\,}{(-8)}</math> | :<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3-\firstcbox{#FFEEAA;}{\,(7-10-5)\,}{(-8)}</math> | ||
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:<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3-\secondcbox{#FFEEAA;}{\,(7-10-5)\,}{(-8)}</math> | :<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3-\secondcbox{#FFEEAA;}{\,(7-10-5)\,}{(-8)}</math> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | and when we remove the brackets in "<math>{}-(-8)</math>" we get "<math>{}+8</math>", | |
:<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3+8</math> | :<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=3+8</math> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
:<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=11.</math> | :<math>\phantom{3-(7-\bbox[#FFEEAA;,1.5pt]{\,(4+6)\,}-5)}{}=11.</math> | ||
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Current revision
The brackets indicate in which order the expression is to be calculated, and we start by calculating the inner bracket.
3−(7−(4+6)−5)=3−(7−10−5) .
Then, we calculate the next bracket.
=3−(7−10−5)
=3−(−8)
and when we remove the brackets in "
=3+8
=11