Processing Math: Done
Solution 1.1:2c
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Robot: Automated text replacement (-[[Bild: +[[Image:)) |
|||
(One intermediate revision not shown.) | |||
Line 1: | Line 1: | ||
{{NAVCONTENT_START}} | {{NAVCONTENT_START}} | ||
- | + | We can divide up the whole expression into two separate parts | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | ||
- | + | which we first calculate and then combine. | |
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | The first part of the expression equals | |
<center><math>3\cdot(-7) = -21</math></center> | <center><math>3\cdot(-7) = -21</math></center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | whilst the second expression becomes. | |
<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | <center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | Combining, we obtain | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | ||
{{NAVCONTENT_STOP}} | {{NAVCONTENT_STOP}} | ||
<!--<center> [[Image:1_1_2c.gif]] </center> --> | <!--<center> [[Image:1_1_2c.gif]] </center> --> |
Current revision
We can divide up the whole expression into two separate parts


which we first calculate and then combine.
The first part of the expression equals

whilst the second expression becomes.


Combining, we obtain

