Solution 1.1:4d
From Förberedande kurs i matematik 1
(Difference between revisions)
(Ny sida: {{NAVCONTENT_START}} <center> Bild:1_1_4d.gif </center> {{NAVCONTENT_STOP}}) |
|||
(3 intermediate revisions not shown.) | |||
Line 1: | Line 1: | ||
- | {{ | + | We have that |
- | <center> [[ | + | :<math>\biggl(\dfrac{4}{\sqrt{2}}\biggr)^2=\dfrac{4^2}{(\sqrt{2}\,)^2}=\dfrac{16}{2}=8</math> |
- | + | is a natural number, integer and rational number. | |
+ | <!--<center> [[Image:1_1_4d.gif]] </center>--> |
Current revision
We have that
- \displaystyle \biggl(\dfrac{4}{\sqrt{2}}\biggr)^2=\dfrac{4^2}{(\sqrt{2}\,)^2}=\dfrac{16}{2}=8
is a natural number, integer and rational number.