From Förberedande kurs i matematik 1

Revision as of 07:48, 29 April 2008 (edit) Tek (Talk | contribs) ← Previous diff		Current revision (13:55, 13 September 2008) (edit) (undo) Ian (Talk | contribs)
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-	Vi har att	+	We have that
	:<math>\biggl(\dfrac{4}{\sqrt{2}}\biggr)^2=\dfrac{4^2}{(\sqrt{2}\,)^2}=\dfrac{16}{2}=8</math>		:<math>\biggl(\dfrac{4}{\sqrt{2}}\biggr)^2=\dfrac{4^2}{(\sqrt{2}\,)^2}=\dfrac{16}{2}=8</math>
-	är ett naturligt tal, heltal och rationellt tal.	+	is a natural number, integer and rational number.
-	<!--<center> [[Bild:1_1_4d.gif]] </center>-->	+	<!--<center> [[Image:1_1_4d.gif]] </center>-->

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Current revision

We have that

\displaystyle \biggl(\dfrac{4}{\sqrt{2}}\biggr)^2=\dfrac{4^2}{(\sqrt{2}\,)^2}=\dfrac{16}{2}=8

is a natural number, integer and rational number.