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Solution 2.2:1c

From Förberedande kurs i matematik 1

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m (Lösning 2.2:1c moved to Solution 2.2:1c: Robot: moved page)
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Because there is an
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<center> [[Image:2_2_1c.gif]] </center>
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<math>x</math>
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on both the left- and right-hand sides,
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the first step is to subtract
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<math>{x}/{3}\;</math>
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from both sides,
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<math>\frac{1}{3}x-1-\frac{1}{3}x=x-\frac{1}{3}x</math>
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so as to collect
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<math>x</math>
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on the right-hand side
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<math>-1=\frac{2}{3}x.</math>
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Then, multiply both sides by
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<math>{3}/{2}\;</math>,
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<math>\frac{3}{2}\centerdot \left( -1 \right)=\frac{3}{2}\centerdot \frac{2}{3}x</math>
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so that
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<math>{2}/{3}\;</math>
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can be eliminated on the right-hand side to give us
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<math>-\frac{3}{2}=x</math>

Revision as of 14:21, 16 September 2008

Because there is an x on both the left- and right-hand sides,

the first step is to subtract x3 from both sides,


31x−1−31x=x−31x


so as to collect x on the right-hand side


−1=32x


Then, multiply both sides by 32,


\displaystyle \frac{3}{2}\centerdot \left( -1 \right)=\frac{3}{2}\centerdot \frac{2}{3}x


so that \displaystyle {2}/{3}\; can be eliminated on the right-hand side to give us


\displaystyle -\frac{3}{2}=x

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