Processing Math: Done
Solution 2.2:1d
From Förberedande kurs i matematik 1
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- | {{ | + | Move |
- | < | + | <math>x</math> |
- | {{ | + | to the left-hand side by subtracting |
+ | <math>2x</math> | ||
+ | from both sides, | ||
+ | |||
+ | |||
+ | <math>5x+7-2x=2x-6-2x</math> | ||
+ | |||
+ | |||
+ | which gives | ||
+ | |||
+ | |||
+ | <math>3x+7=-6</math> | ||
+ | |||
+ | |||
+ | Subtract | ||
+ | <math>7</math> | ||
+ | from both sides, | ||
+ | |||
+ | |||
+ | <math>3x+7-7=-6-7</math> | ||
+ | |||
+ | |||
+ | so that the term | ||
+ | <math>3x</math> | ||
+ | alone remains on the left-hand side | ||
+ | |||
+ | |||
+ | <math>3x=-13</math> | ||
+ | |||
+ | |||
+ | Then, divide both sides by | ||
+ | <math>3</math> | ||
+ | |||
+ | |||
+ | |||
+ | <math>\frac{3x}{3}=-\frac{13}{3}</math> | ||
+ | |||
+ | |||
+ | to get x: | ||
+ | |||
+ | |||
+ | <math>x=-\frac{13}{3}</math> |
Revision as of 14:28, 16 September 2008
Move
which gives
Subtract
so that the term
Then, divide both sides by
to get x: