Loading http://wiki.math.se/jsMath/fonts/msam10/def.js
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution 2.2:5b

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 2.2:5b moved to Solution 2.2:5b: Robot: moved page)
Line 1: Line 1:
 +
Because the straight line is to have a gradient of
 +
<math>-3</math>, its equation can be written as
 +
 +
 +
<math>y=-3x+m</math>
 +
 +
 +
where
 +
<math>m</math>
 +
is a constant. If the line is also to pass through the point
 +
<math>\left( x \right.,\left. y \right)=\left( 1 \right.,\left. -2 \right)</math>, the point
 +
must satisfy the equation of the line
 +
 +
 +
<math>-2=-3\centerdot 1+m</math>
 +
 +
 +
which gives that
 +
<math>m=1</math>.
 +
 +
The answer is thus that the equation of the line is
 +
<math>y=-3x+1</math>.
 +
 +
{{NAVCONTENT_START}}
{{NAVCONTENT_START}}
-
<center> [[Image:2_2_5b.gif]] </center>
+
 
[[Image:1_2_2_5_b_ss1.jpg|center|300px]]
[[Image:1_2_2_5_b_ss1.jpg|center|300px]]
{{NAVCONTENT_STOP}}
{{NAVCONTENT_STOP}}

Revision as of 09:13, 18 September 2008

Because the straight line is to have a gradient of −3, its equation can be written as


y=−3x+m


where m is a constant. If the line is also to pass through the point xy=1−2 , the point must satisfy the equation of the line


\displaystyle -2=-3\centerdot 1+m


which gives that \displaystyle m=1.

The answer is thus that the equation of the line is \displaystyle y=-3x+1.


Retrieved from "http://wiki.math.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_2.2:5b"