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Solution 2.2:5e

From Förberedande kurs i matematik 1

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m (Lösning 2.2:5e moved to Solution 2.2:5e: Robot: moved page)
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The line should go through the points
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<math>\left( 5 \right.,\left. 0 \right)</math>
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and
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<math>\left( 0 \right.,\left. -8 \right)</math>
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which must therefore satisfy the equation of the line
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<math>y=kx+m</math>, i.e.
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 +
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<math>0=k\centerdot 5+m</math>
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 +
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From the other equation, we get
 +
<math>m=-8</math>
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and substituting this into the first equation gives
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 +
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<math>0=5k-8\ \Leftrightarrow \ k={8}/{5}\;</math>
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The gradient of the line is
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<math>{8}/{5}\;</math>.
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 +
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Revision as of 10:05, 18 September 2008

The line should go through the points 50  and 0−8  which must therefore satisfy the equation of the line y=kx+m, i.e.


0=k5+m


From the other equation, we get m=−8 and substituting this into the first equation gives


0=5k−8  k=85


The gradient of the line is 85.


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