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Solution 2.2:6c

From Förberedande kurs i matematik 1

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m (Lösning 2.2:6c moved to Solution 2.2:6c: Robot: moved page)
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The point of intersection is that point which satisfies the equations of both lines
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<math>4x+5y+6=0</math>
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and
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<math>x=0</math>.
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Substituting
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<math>4x+5y+6=0</math>
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into
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<math>x=0</math>
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gives
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<math>4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}</math>
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This gives the point of intersection as
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<math>\left( 0 \right.,\left. -\frac{6}{5} \right)</math>.
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<center> [[Image:2_2_6c.gif]] </center>
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[[Image:2_2_6_c.gif|center]]
[[Image:2_2_6_c.gif|center]]
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Revision as of 11:34, 18 September 2008

The point of intersection is that point which satisfies the equations of both lines


4x+5y+6=0 and x=0.

Substituting 4x+5y+6=0 into x=0 gives


\displaystyle 4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}


This gives the point of intersection as \displaystyle \left( 0 \right.,\left. -\frac{6}{5} \right).


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