Solution 1.1:5a

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2, 3/5, 5/3 and 7/3 .
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<center> [[Image:1_1_5a.gif]] </center>
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It is easier to see the mutual order of the numbers if we write them as decimals.
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Because we know that
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<math>{1}/{5}\;=0.2</math>
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and
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<math>{1}/{3}\;=0.333...</math>, we obtain
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<math>\begin{align}
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& \frac{3}{5}=3\centerdot \frac{3}{5}=3.02=0.6 \\
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& \\
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& \frac{5}{3}=\frac{3+2}{3}=1+\frac{2}{3}=1.666... \\
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& \\
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& \frac{7}{3}=\frac{6+1}{3}=2+\frac{1}{3}=2.333... \\
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\end{align}</math>
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and then we see that.
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<math>\begin{align}
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& \frac{3}{5}<\frac{5}{3}<2<\frac{7}{3} \\
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& \\
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\end{align}</math>

Current revision

2, 3/5, 5/3 and 7/3 .

It is easier to see the mutual order of the numbers if we write them as decimals.

Because we know that \displaystyle {1}/{5}\;=0.2 and \displaystyle {1}/{3}\;=0.333..., we obtain


\displaystyle \begin{align} & \frac{3}{5}=3\centerdot \frac{3}{5}=3.02=0.6 \\ & \\ & \frac{5}{3}=\frac{3+2}{3}=1+\frac{2}{3}=1.666... \\ & \\ & \frac{7}{3}=\frac{6+1}{3}=2+\frac{1}{3}=2.333... \\ \end{align}

and then we see that.


\displaystyle \begin{align} & \frac{3}{5}<\frac{5}{3}<2<\frac{7}{3} \\ & \\ \end{align}

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