Solution 1.1:5a

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Current revision (09:14, 22 September 2008) (edit) (undo)
 
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2, 3/5, 5/3 and 7/3 .
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It is easier to see the mutual order of the numbers if we write them as decimals.
It is easier to see the mutual order of the numbers if we write them as decimals.
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& \\
& \\
& \frac{7}{3}=\frac{6+1}{3}=2+\frac{1}{3}=2.333... \\
& \frac{7}{3}=\frac{6+1}{3}=2+\frac{1}{3}=2.333... \\
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\end{align}</math>
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and then we see that.
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<math>\begin{align}
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& \frac{3}{5}<\frac{5}{3}<2<\frac{7}{3} \\
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& \\
\end{align}</math>
\end{align}</math>

Current revision

2, 3/5, 5/3 and 7/3 .

It is easier to see the mutual order of the numbers if we write them as decimals.

Because we know that \displaystyle {1}/{5}\;=0.2 and \displaystyle {1}/{3}\;=0.333..., we obtain


\displaystyle \begin{align} & \frac{3}{5}=3\centerdot \frac{3}{5}=3.02=0.6 \\ & \\ & \frac{5}{3}=\frac{3+2}{3}=1+\frac{2}{3}=1.666... \\ & \\ & \frac{7}{3}=\frac{6+1}{3}=2+\frac{1}{3}=2.333... \\ \end{align}

and then we see that.


\displaystyle \begin{align} & \frac{3}{5}<\frac{5}{3}<2<\frac{7}{3} \\ & \\ \end{align}

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