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Solution 2.1:1f

From Förberedande kurs i matematik 1

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Current revision (07:56, 23 September 2008) (edit) (undo)
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The squaring rule <math> (a+b)^2 = a^2+2ab+b^2</math> with <math>a=5 </math> and <math> b=4y </math> gives
The squaring rule <math> (a+b)^2 = a^2+2ab+b^2</math> with <math>a=5 </math> and <math> b=4y </math> gives
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<math>\qquad \begin{align} (5+4y)^2 &= 5^2+ 2\cdot 5 \cdot 4y +(4y)^2 \\
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{{Displayed math||<math>\begin{align}
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&= 25+10\cdot 4y + 4^2y^2\\
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(5+4y)^2 &= 5^2+ 2\cdot 5 \cdot 4y +(4y)^2 \\[3pt]
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&= 25+40y+16y^4\\
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&= 25+10\cdot 4y + 4^2y^2\\[3pt]
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&= 16y^2 +40y 25
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&= 25+40y+16y^2\\[3pt]
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\end{align}
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&= 16y^2 +40y + 25\,\textrm{.}
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</math>
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\end{align}</math>}}
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Current revision

The squaring rule (a+b)2=a2+2ab+b2 with a=5 and b=4y gives

(5+4y)2=52+254y+(4y)2=25+104y+42y2=25+40y+16y2=16y2+40y+25.
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