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Solution 2.1:3e

From Förberedande kurs i matematik 1

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Current revision (08:37, 23 September 2008) (edit) (undo)
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Both terms contain ''x'', which can therefore be taken out as a factor (as can 2),
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{{Displayed math||<math>18x-2x^3=2x\cdot 9-2x \cdot x^2=2x(9-x^2)\,\textrm{.}</math>}}
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The remaining second-degree factor <math> 9-x^2 </math> can then be factorized using the conjugate rule
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{{Displayed math||<math> 2x(9-x^2)=2x(3^2-x^2)=2x(3+x)(3-x)\,,</math>}}
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which can also be written as <math>-2x(x+3)(x-3).</math>

Current revision

Both terms contain x, which can therefore be taken out as a factor (as can 2),

18x2x3=2x92xx2=2x(9x2).

The remaining second-degree factor 9x2 can then be factorized using the conjugate rule

2x(9x2)=2x(32x2)=2x(3+x)(3x)

which can also be written as 2x(x+3)(x3)