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Solution 2.1:3f

From Förberedande kurs i matematik 1

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Current revision (08:39, 23 September 2008) (edit) (undo)
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Treating <math>4x</math> as one term, we can write
Treating <math>4x</math> as one term, we can write
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<math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math>
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{{Displayed math||<math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math>}}
and since <math> y^2 +2y+1=(y+1)^2 </math> we obtain
and since <math> y^2 +2y+1=(y+1)^2 </math> we obtain
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<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math>
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{{Displayed math||<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math>.}}
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<!--<center> [[Bild:2_1_3f.gif]] </center>-->
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Current revision

Treating 4x as one term, we can write

16x2+8x+1=(4x)2+24x+1

and since y2+2y+1=(y+1)2 we obtain

(4x)2+24x+1=(4x+1)2.
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