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Solution 2.2:5b

From Förberedande kurs i matematik 1

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Current revision (12:28, 24 September 2008) (edit) (undo)
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Because the straight line is to have a slope of <math>-3</math>, its equation can be written as
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<center> [[Bild:2_2_5b.gif]] </center>
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{{Displayed math||<math>y=-3x+m\,,</math>}}
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<center> [[Bild:s1_2_2_5_b.jpg]]
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where ''m'' is a constant. If the line is also to pass through the point (''x'',''y'')&nbsp;= (1,-2), the point must satisfy the equation of the line,
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{{Displayed math||<math>-2=-3\cdot 1+m\,,</math>}}
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which gives that <math>m=1</math>.
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The answer is thus that the equation of the line is <math>y=-3x+1</math>.
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[[Image:1_2_2_5_b_ss1.jpg|center|300px]]

Current revision

Because the straight line is to have a slope of −3, its equation can be written as

y=−3x+m

where m is a constant. If the line is also to pass through the point (x,y) = (1,-2), the point must satisfy the equation of the line,

−2=−31+m

which gives that m=1.

The answer is thus that the equation of the line is y=−3x+1.


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