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Solution 2.2:6c

From Förberedande kurs i matematik 1

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Current revision (13:10, 24 September 2008) (edit) (undo)
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The point of intersection is that point which satisfies the equations of both lines
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<center> [[Bild:2_2_6c.gif]] </center>
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[[Bild:2_2_6_c.gif|center]]
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{{Displayed math||<math>4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.}</math>}}
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Substituting <math>x=0</math> into <math>4x+5y+6=0</math> gives
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{{Displayed math||<math>4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.}</math>}}
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This gives the point of intersection as <math>\bigl(0,-\tfrac{6}{5}\bigr)</math>.
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<center>[[Image:2_2_6_c.gif|center]]</center>

Current revision

The point of intersection is that point which satisfies the equations of both lines

4x+5y+6=0andx=0.

Substituting x=0 into 4x+5y+6=0 gives

40+5y+6=0y=−56.

This gives the point of intersection as 0−56 .


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